Kayode - Maths teacher - Port Harcourt
1st class free
Kayode - Maths teacher - Port Harcourt

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Kayode

  • Rate ₹355
  • Response 24h
  • Students

    Number of students accompanied by Kayode since their arrival at Superprof

    1

    Number of students accompanied by Kayode since their arrival at Superprof

Kayode - Maths teacher - Port Harcourt
  • 5 (2 reviews)

₹355/hr

1st class free

Contact

1st class free

1st class free

  • Maths
  • Trigonometry
  • Arithmetic
  • Geometry
  • Logic

A dynamic and proficient Math tutor, incorporating sound knowledge of Engineering and Science to solving your mathematical problems. I teach the "understanding" of Math to aid your strength in not j

  • Maths
  • Trigonometry
  • Arithmetic
  • Geometry
  • Logic

Class location

Recommended

Kayode is a respected tutor in our community. He is highly recommended for his commitment and the quality of his lessons. An excellent choice to progress with confidence.

About Kayode

I am a Civil Engineer but I've been passionate about teaching. I presently take home lessons and online tutorials in some other platforms. I engage the teaching of basic principle of mathematics and engineering to expose students to the concept behind each Mathematical problem and hence stir up your interest in not just the questions but the topic as a whole. Once you get the understanding of Mathematics, you can easily solve any question even beyond the scope of the particular question.

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About the class

  • Classes 1 to 5
  • Classes 6 to 8
  • Class 10
  • +9
  • levels :

    Classes 1 to 5

    Classes 6 to 8

    Class 10

    Classes 11 & 12

    Class 12

    Adult Literacy

    Undergraduate

    Masters

    PG Diploma

    PhD

    MBA

    Kindergarten (LKG, UKG)

  • English

All languages in which the class is available :

English

Find the largest of three consecutive odd numbers whose sum is 57. Solution: Let the largest be x Consecutive odd numbers increase/decrease by difference of 2. This implies, other two numbers are (x-2) and (x-4) So, the sum; x + (x-2) + (x-4) = 57 Hence, solving, we have; 3x - 6= 57 Add 6 to both sides, 3x = 63 Dividing both sides by 3 X = 21. This implies that, the largest number is 21. Other two numbers are; X-2 => 21-2 = 19 X-4 => 21-4 = 17 Check: The sum = 21+19+17= 57

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Rates

Rate

  • ₹355

Pack prices

  • 5h: ₹1,775
  • 10h: ₹3,550

free classes

This first free class with Kayode will allow you to get to know each other and to specify the exact learning requirements for the upcoming classes.

  • 30mins

online

  • ₹-36/hr

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