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Jitendra
- Rate ₹1,000
- Response 1h
₹1,000/hr
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- Arithmetic
Learn arithmetic in easy way with lots of trick... It's surely going to be amazing..
- Arithmetic
Class location
-
At Jitendra 's house : Naugaon
- Online
-
About Jitendra
I have taught tuition in Maths and English.
I am a Mechanical Engineer and preparing for various exams so I basically deals with various tricks to solve Quantitative aptitude questions also.
As we all know many people gives exam and for a particular question their is a time of 1.5 minute atmost with respect to various exams, so tricks plays a great role over here....
So let's make the questions easier and morever save time by playing with Maths in a different way...
I will be teaching with all basic concepts and I am sure you will be loving it.
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About the class
- Classes 1 to 5
- Class 12
- Adult Literacy
- +2
levels :
Classes 1 to 5
Class 12
Adult Literacy
Masters
PhD
- English
All languages in which the class is available :
English
Here we will solve Time, distance and speed question with tricks in just 30 seconds...
1)In case1, a person travels at 4 km/ hr from A to B, he becomes 20 min late,
In case 2, he travels with 6 km/ hr, then he reaches B point 10 min. Early.
Find the distance between A and B point?
We will solve this question with both methods , conventional and with trick, and you yourself will realise the need of trick...
CONVENTIONAL METHOD:
Let the distance between A and B point is D km and the usual speed of person be S km/ hr to reach him in time.
(D/4)-(D/S)=(20/60)-------- Eq. 1
(D/S)-(D/6)=(10/60)-------- Eq. 2
Now you people have to solve these equations and find the value of D ....
And definitely this is going to take 5 min. Approx...
So let's tune up to tricks
TRICK
Just 4 steps and the question is finished in 30 seconds...
Step1- Work for change in speed with respect to initial speed
Speed changes( increases) from 4 km/ hr to 6 km/ hr, so
Change in speed= 1/2
i.e [change in speed= change in speed( 6-4)/ initial or former speed]✓
=(6-4)/4
= 1/2
If speed increases in the ratio 1/2, then time decreases in the ratio (1/3)
[How this happen is also a trick, I will tell it later]✓
We know that difference between 20 min late and 10 min early is 30 minutes or 0.5 hr
So just apply
Step 2-
( 1/3)of T= 30 min
T= 90 min or 1.5 hr, here T is the original time that will be taken by the person when moving with 4 km/ hr to reach B point.
Step 3-
clearly distance = speed × Time
Distance= 4 × 1.5
= 6 km
I hope it will not take more than 30 seconds to get the ans. With this trick
More TRICKS on the way.....
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Rates
Rate
- ₹1,000
Pack prices
- 5h: ₹5
- 10h: ₹10
online
- ₹1,000/hr
Details
My rates will be different for different class students and morever will also be based on various conditions.
The rates will be adjustable, so no need to worry about that.
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