1st class free
Aarya profile and their contact details have been verified by our experts
Aarya
- Rate ₹300
- Response 3h
-
Students1
Number of students accompanied by Aarya since their arrival at Superprof
Number of students accompanied by Aarya since their arrival at Superprof
₹300/hr
Contact
1st class free
- Maths
- Algebra
- Trigonometry
- Arithmetic
- Geometry
2nd year engineering student pursuing ECE from Vellore Institute of Technology, proficient in mental maths and problem solving
- Maths
- Algebra
- Trigonometry
- Arithmetic
- Geometry
Class location
Recommended
Aarya is a respected tutor in our community. He is highly recommended for his commitment and the quality of his lessons. An excellent choice to progress with confidence.
About Aarya
As a kid, I found math to be just another subject filled with boring books and endless memorization. It never felt exciting—until I started turning it into games. Instead of just solving problems, I played with numbers, turning equations into puzzles and challenges. Now, as an engineering student, I use the same approach to teach my roommates, friends, and even my younger cousins. Watching them go from fearing math to enjoying it, sharpening their skills along the way, has been incredibly rewarding. Math is no longer a ghost to them—it’s just another puzzle waiting to be solved.
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About the class
- Classes 1 to 5
- Classes 6 to 8
- Class 10
- +2
levels :
Classes 1 to 5
Classes 6 to 8
Class 10
Classes 11 & 12
Kindergarten (LKG, UKG)
- English
- Hindi
- Bengali
All languages in which the class is available :
English
Hindi
Bengali
Aren't you bored of studying trigonometry in the same old way what if you are an explorer searching for an ancient relic hidden deep in a lost temple. The only way to navigate through obstacles and find the relic is by using trigonometry!
Challenge 1: The Rope Bridge (Right Triangle Basics)
You reach a broken rope bridge across a canyon. A tree stands 20m away, and a vine is tied 30m up in the tree. You need to calculate the angle at which you must swing to reach the other side safely.
Problem:
Find θ, where:
Opposite = 30m (height of the tree)
Adjacent = 20m (distance to the tree)
tan(θ) = opposite/adjacent
Solution:
θ = tan⁻¹(30/20) = tan⁻¹(1.5) ≈ 56.3°
Simple enough isn't it well it can be even more fun and insightful with me not only for trigonometry but for anything that you can think of at this point in mathematics you name it and you learn it easily with me.
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Recommendations
Recommendations come from relatives, friends and acquaintances of the teacher
3
She was absolutely great and phenomenon with her concepts and methods of teaching. Cleared almost all my doubts in the most unique way to think of. Totally recommended
She's a talented child. Taught my daughter with complete dedication and is very well versed with her work and her concepts
Trustworthy and wonderful teacher. Crisp and clear concepts. Uniqueness in teaching. Simple methods
View more recommendations
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Rates
Rate
- ₹300
Pack prices
- 5h: ₹1,450
- 10h: ₹2,500
online
- ₹300/hr
free classes
This first free class with Aarya will allow you to get to know each other and to specify the exact learning requirements for the upcoming classes.
- 1hr
Details
Will include personally dedicated 1 hour to the student, the fees includes extra doubt sessions and tests and quizzes as well
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